(t)/(t-4)+3=(4)/(t-4)

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Solution for (t)/(t-4)+3=(4)/(t-4) equation: 


D( t )

t-4 = 0

t-4 = 0

t-4 = 0

t-4 = 0 // + 4

t = 4

t in (-oo:4) U (4:+oo)

t/(t-4)+3 = 4/(t-4) // - 4/(t-4)

t/(t-4)-(4/(t-4))+3 = 0

t/(t-4)-4*(t-4)^-1+3 = 0

t/(t-4)-4/(t-4)+3 = 0

t/(t-4)-4/(t-4)+(3*(t-4))/(t-4) = 0

3*(t-4)+t-4 = 0

t+3*t-12-4 = 0

4*t-16 = 0

(4*t-16)/(t-4) = 0

(4*t-16)/(t-4) = 0 // * t-4

4*t-16 = 0

4*t-16 = 0 // + 16

4*t = 16 // : 4

t = 16/4

t = 4

t in { 4} 

t belongs to the empty set

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