(t)=-16t2+64t+70

Solution for (t)=-16t2+64t+70 equation:

(t)=-16t^2+64t+70

We move all terms to the left:

(t)-(-16t^2+64t+70)=0

We get rid of parentheses

16t^2-64t+t-70=0

We add all the numbers together, and all the variables

16t^2-63t-70=0

a = 16; b = -63; c = -70;
Δ = b2-4ac
Δ = -632-4·16·(-70)
Δ = 8449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{8449}}{2*16}=\frac{63-\sqrt{8449}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{8449}}{2*16}=\frac{63+\sqrt{8449}}{32}
$