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(t)=-16t^2+64t+70
We move all terms to the left:
(t)-(-16t^2+64t+70)=0
We get rid of parentheses
16t^2-64t+t-70=0
We add all the numbers together, and all the variables
16t^2-63t-70=0
a = 16; b = -63; c = -70;
Δ = b2-4ac
Δ = -632-4·16·(-70)
Δ = 8449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{8449}}{2*16}=\frac{63-\sqrt{8449}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{8449}}{2*16}=\frac{63+\sqrt{8449}}{32} $
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