(t+-3)-7=(6t+2)

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Solution for (t+-3)-7=(6t+2) equation: 



(t+-3)-7=(6t+2)

We move all terms to the left:

(t+-3)-7-((6t+2))=0

We add all the numbers together, and all the variables

(t-3)-((6t+2))-7=0

We get rid of parentheses

t-((6t+2))-3-7=0



We calculate terms in parentheses: -((6t+2)), so:

(6t+2)

We get rid of parentheses

6t+2

Back to the equation:

-(6t+2)



We add all the numbers together, and all the variables

t-(6t+2)-10=0

We get rid of parentheses

t-6t-2-10=0

We add all the numbers together, and all the variables

-5t-12=0

We move all terms containing t to the left, all other terms to the right

-5t=12

t=12/-5

t=-2+2/5

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