(t+1)(t+1)*(t-8)(t-8)=45

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Solution for (t+1)(t+1)*(t-8)(t-8)=45 equation: 



(t+1)(t+1)(t-8)(t-8)=45

We move all terms to the left:

(t+1)(t+1)(t-8)(t-8)-(45)=0

We multiply parentheses ..

(+t^2+t+t+1)(t-8)(t-8)-45=0

We multiply parentheses ..

(+t^2+t+t+1)(+t^2-8t-8t+64)-45=0

We move all terms containing t to the left, all other terms to the right

(+t^2+t+t+1)(+t^2-8t-8t+64)=45

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