(t+1)*3+(2*t)*4=0

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Solution for (t+1)*3+(2*t)*4=0 equation:


Simplifying
(t + 1) * 3 + (2t) * 4 = 0

Reorder the terms:
(1 + t) * 3 + (2t) * 4 = 0

Reorder the terms for easier multiplication:
3(1 + t) + (2t) * 4 = 0
(1 * 3 + t * 3) + (2t) * 4 = 0
(3 + 3t) + (2t) * 4 = 0

Remove parenthesis around (2t)
3 + 3t + 2t * 4 = 0

Reorder the terms for easier multiplication:
3 + 3t + 2 * 4t = 0

Multiply 2 * 4
3 + 3t + 8t = 0

Combine like terms: 3t + 8t = 11t
3 + 11t = 0

Solving
3 + 11t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 11t = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 11t = 0 + -3
11t = 0 + -3

Combine like terms: 0 + -3 = -3
11t = -3

Divide each side by '11'.
t = -0.2727272727

Simplifying
t = -0.2727272727

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