(t+2)(t+2)=4

Solution for (t+2)(t+2)=4 equation:

Simplifying
(t + 2)(t + 2) = 4

Reorder the terms:
(2 + t)(t + 2) = 4

Reorder the terms:
(2 + t)(2 + t) = 4

Multiply (2 + t) * (2 + t)
(2(2 + t) + t(2 + t)) = 4
((2 * 2 + t * 2) + t(2 + t)) = 4
((4 + 2t) + t(2 + t)) = 4
(4 + 2t + (2 * t + t * t)) = 4
(4 + 2t + (2t + t2)) = 4

Combine like terms: 2t + 2t = 4t
(4 + 4t + t2) = 4

Add '-4' to each side of the equation.
4 + 4t + -4 + t2 = 4 + -4

Reorder the terms:
4 + -4 + 4t + t2 = 4 + -4

Combine like terms: 4 + -4 = 0
0 + 4t + t2 = 4 + -4
4t + t2 = 4 + -4

Combine like terms: 4 + -4 = 0
4t + t2 = 0

Solving
4t + t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), 't'.
t(4 + t) = 0

Subproblem 1
Set the factor 't' equal to zero and attempt to solve:

Simplifying
t = 0

Solving
t = 0

Move all terms containing t to the left, all other terms to the right.

Simplifying
t = 0
Subproblem 2
Set the factor '(4 + t)' equal to zero and attempt to solve:

Simplifying
4 + t = 0

Solving
4 + t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + t = 0 + -4

Combine like terms: 4 + -4 = 0
0 + t = 0 + -4
t = 0 + -4

Combine like terms: 0 + -4 = -4
t = -4

Simplifying
t = -4
Solution
t = {0, -4}