(t+28)(t-32)=0

Solution for (t+28)(t-32)=0 equation:

Simplifying
(t + 28)(t + -32) = 0

Reorder the terms:
(28 + t)(t + -32) = 0

Reorder the terms:
(28 + t)(-32 + t) = 0

Multiply (28 + t) * (-32 + t)
(28(-32 + t) + t(-32 + t)) = 0
((-32 * 28 + t * 28) + t(-32 + t)) = 0
((-896 + 28t) + t(-32 + t)) = 0
(-896 + 28t + (-32 * t + t * t)) = 0
(-896 + 28t + (-32t + t2)) = 0

Combine like terms: 28t + -32t = -4t
(-896 + -4t + t2) = 0

Solving
-896 + -4t + t2 = 0

Solving for variable 't'.

Factor a trinomial.
(-28 + -1t)(32 + -1t) = 0

Subproblem 1
Set the factor '(-28 + -1t)' equal to zero and attempt to solve:

Simplifying
-28 + -1t = 0

Solving
-28 + -1t = 0

Move all terms containing t to the left, all other terms to the right.

Add '28' to each side of the equation.
-28 + 28 + -1t = 0 + 28

Combine like terms: -28 + 28 = 0
0 + -1t = 0 + 28
-1t = 0 + 28

Combine like terms: 0 + 28 = 28
-1t = 28

Divide each side by '-1'.
t = -28

Simplifying
t = -28
Subproblem 2
Set the factor '(32 + -1t)' equal to zero and attempt to solve:

Simplifying
32 + -1t = 0

Solving
32 + -1t = 0

Move all terms containing t to the left, all other terms to the right.

Add '-32' to each side of the equation.
32 + -32 + -1t = 0 + -32

Combine like terms: 32 + -32 = 0
0 + -1t = 0 + -32
-1t = 0 + -32

Combine like terms: 0 + -32 = -32
-1t = -32

Divide each side by '-1'.
t = 32

Simplifying
t = 32
Solution
t = {-28, 32}