(t+28)/3=11

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Solution for (t+28)/3=11 equation: 



(t+28)/3=11

We move all terms to the left:

(t+28)/3-(11)=0

We multiply all the terms by the denominator


(t+28)-11*3=0

We add all the numbers together, and all the variables

(t+28)-33=0

We get rid of parentheses

t+28-33=0

We add all the numbers together, and all the variables

t-5=0

We move all terms containing t to the left, all other terms to the right

t=5

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