(t+3)(t+8)=t(t-5))+168

Solution for (t+3)(t+8)=t(t-5))+168 equation:

(t+3)(t+8)=t(t-5))+168

We move all terms to the left:

(t+3)(t+8)-(t(t-5))+168)=0

We add all the numbers together, and all the variables

(t+3)(t+8)-(t(t-5))=0

We multiply parentheses ..

(+t^2+8t+3t+24)-(t(t-5))=0


We calculate terms in parentheses: -(t(t-5)), so:

t(t-5)

We multiply parentheses

t^2-5t

Back to the equation:

-(t^2-5t)


We get rid of parentheses

t^2-t^2+8t+3t+5t+24=0

We add all the numbers together, and all the variables

16t+24=0

We move all terms containing t to the left, all other terms to the right

16t=-24

t=-24/16

t=-1+1/2