(t+3)=2(t+5)=34

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Solution for (t+3)=2(t+5)=34 equation: 



(t+3)=2(t+5)=34

We move all terms to the left:

(t+3)-(2(t+5))=0

We get rid of parentheses

t-(2(t+5))+3=0



We calculate terms in parentheses: -(2(t+5)), so:

2(t+5)

We multiply parentheses

2t+10

Back to the equation:

-(2t+10)



We get rid of parentheses

t-2t-10+3=0

We add all the numbers together, and all the variables

-1t-7=0

We move all terms containing t to the left, all other terms to the right

-t=7

t=7/-1

t=-7

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