(t+5)(t-5)=t+6)(t-7)+8

Solution for (t+5)(t-5)=t+6)(t-7)+8 equation:

(t+5)(t-5)=t+6)(t-7)+8

We move all terms to the left:

(t+5)(t-5)-(t+6)(t-7)+8)=0

We add all the numbers together, and all the variables

(t+5)(t-5)-(t+6)(t-7)=0

We use the square of the difference formula

t^2-(t+6)(t-7)-25=0

We multiply parentheses ..

t^2-(+t^2-7t+6t-42)-25=0

We get rid of parentheses

t^2-t^2+7t-6t+42-25=0

We add all the numbers together, and all the variables

t+17=0

We move all terms containing t to the left, all other terms to the right

t=-17