(t+5)/16+(t-3)/16=(6t+1)/8

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Solution for (t+5)/16+(t-3)/16=(6t+1)/8 equation: 



(t+5)/16+(t-3)/16=(6t+1)/8

We move all terms to the left:

(t+5)/16+(t-3)/16-((6t+1)/8)=0

We calculate fractions


2t/()+(-((6t+1)*16)/()=0



We calculate terms in parentheses: +(-((6t+1)*16)/(), so:

-((6t+1)*16)/(

We multiply all the terms by the denominator


-((6t+1)*16)



We calculate terms in parentheses: -((6t+1)*16), so:

(6t+1)*16

We multiply parentheses

96t+16

Back to the equation:

-(96t+16)



We get rid of parentheses

-96t-16

Back to the equation:

+(-96t-16)



We get rid of parentheses

2t/()-96t-16=0

We multiply all the terms by the denominator


2t-96t*()-16*()=0

We add all the numbers together, and all the variables

2t-96t*()=0

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