(t+6)/5=(t-2)/10

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Solution for (t+6)/5=(t-2)/10 equation: 



(t+6)/5=(t-2)/10

We move all terms to the left:

(t+6)/5-((t-2)/10)=0

We calculate fractions


t/()+(-((t-2)*5)/()=0



We calculate terms in parentheses: +(-((t-2)*5)/(), so:

-((t-2)*5)/(

We multiply all the terms by the denominator


-((t-2)*5)



We calculate terms in parentheses: -((t-2)*5), so:

(t-2)*5

We multiply parentheses

5t-10

Back to the equation:

-(5t-10)



We get rid of parentheses

-5t+10

Back to the equation:

+(-5t+10)



We get rid of parentheses

t/()-5t+10=0

We multiply all the terms by the denominator


t-5t*()+10*()=0

We add all the numbers together, and all the variables

t-5t*()=0

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