(t-1)/9=(t-2)/2

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Solution for (t-1)/9=(t-2)/2 equation: 



(t-1)/9=(t-2)/2

We move all terms to the left:

(t-1)/9-((t-2)/2)=0

We calculate fractions


t/()+(-((t-2)*9)/()=0



We calculate terms in parentheses: +(-((t-2)*9)/(), so:

-((t-2)*9)/(

We multiply all the terms by the denominator


-((t-2)*9)



We calculate terms in parentheses: -((t-2)*9), so:

(t-2)*9

We multiply parentheses

9t-18

Back to the equation:

-(9t-18)



We get rid of parentheses

-9t+18

Back to the equation:

+(-9t+18)



We get rid of parentheses

t/()-9t+18=0

We multiply all the terms by the denominator


t-9t*()+18*()=0

We add all the numbers together, and all the variables

t-9t*()=0

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