(t-12/2)=(3t/2)-3

Solution for (t-12/2)=(3t/2)-3 equation:

(t-12/2)=(3t/2)-3

We move all terms to the left:

(t-12/2)-((3t/2)-3)=0

We add all the numbers together, and all the variables

(t-6)-((+3t/2)-3)=0

We get rid of parentheses

t-((+3t/2)-3)-6=0

We multiply all the terms by the denominator


t*2)-3)-((+3t-6*2)-3)=0

We add all the numbers together, and all the variables

t*2)-3)-((3t-12)-3)=0

We add all the numbers together, and all the variables

t*2)-3)-((3t=0

Wy multiply elements

2t^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{4}=0$