(t-2)(t+2)=5

Solution for (t-2)(t+2)=5 equation:

Simplifying
(t + -2)(t + 2) = 5

Reorder the terms:
(-2 + t)(t + 2) = 5

Reorder the terms:
(-2 + t)(2 + t) = 5

Multiply (-2 + t) * (2 + t)
(-2(2 + t) + t(2 + t)) = 5
((2 * -2 + t * -2) + t(2 + t)) = 5
((-4 + -2t) + t(2 + t)) = 5
(-4 + -2t + (2 * t + t * t)) = 5
(-4 + -2t + (2t + t2)) = 5

Combine like terms: -2t + 2t = 0
(-4 + 0 + t2) = 5
(-4 + t2) = 5

Solving
-4 + t2 = 5

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + t2 = 5 + 4

Combine like terms: -4 + 4 = 0
0 + t2 = 5 + 4
t2 = 5 + 4

Combine like terms: 5 + 4 = 9
t2 = 9

Simplifying
t2 = 9

Take the square root of each side:
t = {-3, 3}