If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( t )
4*t-16 = 0
2*t-8 = 0
4*t-16 = 0
4*t-16 = 0
4*t-16 = 0 // + 16
4*t = 16 // : 4
t = 16/4
t = 4
2*t-8 = 0
2*t-8 = 0
2*t-8 = 0 // + 8
2*t = 8 // : 2
t = 8/2
t = 4
t in (-oo:4) U (4:+oo)
(t-2)/(2*t-8) = 5/(4*t-16) // - 5/(4*t-16)
(t-2)/(2*t-8)-(5/(4*t-16)) = 0
(t-2)/(2*t-8)-5*(4*t-16)^-1 = 0
(t-2)/(2*t-8)-5/(4*t-16) = 0
((t-2)*(4*t-16))/((2*t-8)*(4*t-16))+(-5*(2*t-8))/((2*t-8)*(4*t-16)) = 0
(t-2)*(4*t-16)-5*(2*t-8) = 0
4*t^2-34*t+72 = 0
4*t^2-34*t+72 = 0
2*(2*t^2-17*t+36) = 0
2*t^2-17*t+36 = 0
DELTA = (-17)^2-(2*4*36)
DELTA = 1
DELTA > 0
t = (1^(1/2)+17)/(2*2) or t = (17-1^(1/2))/(2*2)
t = 9/2 or t = 4
2*(t-4)*(t-9/2) = 0
(2*(t-4)*(t-9/2))/((2*t-8)*(4*t-16)) = 0
(2*(t-4)*(t-9/2))/((2*t-8)*(4*t-16)) = 0 // * (2*t-8)*(4*t-16)
2*(t-4)*(t-9/2) = 0
( 2 )
2 = 0
t belongs to the empty set
( t-4 )
t-4 = 0 // + 4
t = 4
( t-9/2 )
t-9/2 = 0 // + 9/2
t = 9/2
t in { 4}
t = 9/2
| (2x^2+y)dx(x^2y-y)dy=0 | | 5+2(3x-1)+4x-1= | | 1-3(4)-2= | | -3n+43=-11 | | C=76 | | a[r+v+z]+3av= | | 6x+2(5x+4+y)= | | -7w+3(w+2)= | | 7x^2-2x=57 | | -2(4w+8)= | | xy+4y=75+5x | | 6x^2-9x+6= | | 5x+2y-x+5y= | | -(2m+n-3p)= | | 4x-1=24-x | | 0=3x+18x+27 | | x^2-4/x^4 | | x-6x=-5 | | x/4=10.7 | | 1/10000 | | 4x+5y=-22 | | 2(x-21)=56-4(x-4) | | 4x-2x^2+30=0 | | ((2a^2)^3)/b | | 2(4)+13=21y | | x^2=16x+63 | | 180-2x+18= | | 2x-10=35 | | 2x+18=3x-13 | | 7x-23=3 | | 3b(b-2)-4(b-2)= | | 5=(3*0)-5 |