(t-3)2-(t-2)2=5

Solution for (t-3)2-(t-2)2=5 equation:

Simplifying
(t + -3) * 2 + -1(t + -2) * 2 = 5

Reorder the terms:
(-3 + t) * 2 + -1(t + -2) * 2 = 5

Reorder the terms for easier multiplication:
2(-3 + t) + -1(t + -2) * 2 = 5
(-3 * 2 + t * 2) + -1(t + -2) * 2 = 5
(-6 + 2t) + -1(t + -2) * 2 = 5

Reorder the terms:
-6 + 2t + -1(-2 + t) * 2 = 5

Reorder the terms for easier multiplication:
-6 + 2t + -1 * 2(-2 + t) = 5

Multiply -1 * 2
-6 + 2t + -2(-2 + t) = 5
-6 + 2t + (-2 * -2 + t * -2) = 5
-6 + 2t + (4 + -2t) = 5

Reorder the terms:
-6 + 4 + 2t + -2t = 5

Combine like terms: -6 + 4 = -2
-2 + 2t + -2t = 5

Combine like terms: 2t + -2t = 0
-2 + 0 = 5
-2 = 5

Solving
-2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.