(t-49)/5=(88.2-t)/9

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Solution for (t-49)/5=(88.2-t)/9 equation: 



(t-49)/5=(88.2-t)/9

We move all terms to the left:

(t-49)/5-((88.2-t)/9)=0

We add all the numbers together, and all the variables

(t-49)/5-((-1t+88.2)/9)=0

We calculate fractions


t/()+(-((-1t+88.2)*5)/()=0



We calculate terms in parentheses: +(-((-1t+88.2)*5)/(), so:

-((-1t+88.2)*5)/(

We multiply all the terms by the denominator


-((-1t+88.2)*5)



We calculate terms in parentheses: -((-1t+88.2)*5), so:

(-1t+88.2)*5

We multiply parentheses

-5t+441

Back to the equation:

-(-5t+441)



We get rid of parentheses

5t-441

Back to the equation:

+(5t-441)



We get rid of parentheses

t/()+5t-441=0

We multiply all the terms by the denominator


t+5t*()-441*()=0

We add all the numbers together, and all the variables

t+5t*()=0

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