(t-5/t-3)=(t-3/t+3)+(1/t-3)

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Solution for (t-5/t-3)=(t-3/t+3)+(1/t-3) equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

t-(5/t)-3 = t-(3/t)+1/t-3+3 // - t-(3/t)+1/t-3+3

t-t-(5/t)+3/t-(1/t)-3-3+3 = 0

t-t-5*t^-1+3/t-t^-1-3-3+3 = 0

-3*t^-1 = 3 // : -3

t^-1 = -1

-1 < 0

1/(t^1) = -1 // * t^1

1 = -1*t^1 // : -1

-1 = t^1

t = -1

t = -1

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