(t/3)=(4/9)

Solution for (t/3)=(4/9) equation:

(t/3)=(4/9)

We move all terms to the left:

(t/3)-((4/9))=0

We add all the numbers together, and all the variables

(+t/3)-((+4/9))=0

We get rid of parentheses

t/3-((+4/9))=0

We calculate fractions


9t^2/()+()/()=0

We add all the numbers together, and all the variables

9t^2/()+1=0

We multiply all the terms by the denominator


9t^2+1*()=0

We add all the numbers together, and all the variables

9t^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{18}=0$