(u)(4u-24)=-36

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Solution for (u)(4u-24)=-36 equation: 



(u)(4u-24)=-36

We move all terms to the left:

(u)(4u-24)-(-36)=0

We add all the numbers together, and all the variables

u(4u-24)+36=0

We multiply parentheses

4u^2-24u+36=0

a = 4; b = -24; c = +36;
Δ = b2-4ac
Δ = -242-4·4·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{24}{8}=3$

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