(u)+(2)+(3u)/(u+2)

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Solution for (u)+(2)+(3u)/(u+2) equation:


D( u )

u+2 = 0

u+2 = 0

u+2 = 0

u+2 = 0 // - 2

u = -2

u in (-oo:-2) U (-2:+oo)

(3*u)/(u+2)+u+2 = 0

(3*u)/(u+2)+(u*(u+2))/(u+2)+(2*(u+2))/(u+2) = 0

u*(u+2)+2*(u+2)+3*u = 0

u^2+5*u+2*u+4 = 0

u^2+7*u+4 = 0

u^2+7*u+4 = 0

u^2+7*u+4 = 0

DELTA = 7^2-(1*4*4)

DELTA = 33

DELTA > 0

u = (33^(1/2)-7)/(1*2) or u = (-33^(1/2)-7)/(1*2)

u = (33^(1/2)-7)/2 or u = (-(33^(1/2)+7))/2

(u+(33^(1/2)+7)/2)*(u-((33^(1/2)-7)/2)) = 0

((u+(33^(1/2)+7)/2)*(u-((33^(1/2)-7)/2)))/(u+2) = 0

((u+(33^(1/2)+7)/2)*(u-((33^(1/2)-7)/2)))/(u+2) = 0 // * u+2

(u+(33^(1/2)+7)/2)*(u-((33^(1/2)-7)/2)) = 0

( u+(33^(1/2)+7)/2 )

u+(33^(1/2)+7)/2 = 0 // - (33^(1/2)+7)/2

u = -((33^(1/2)+7)/2)

( u-((33^(1/2)-7)/2) )

u-((33^(1/2)-7)/2) = 0 // + (33^(1/2)-7)/2

u = (33^(1/2)-7)/2

u in { -((33^(1/2)+7)/2), (33^(1/2)-7)/2 }

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