(u+2/3u-1)+1=6-u/u+1

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Solution for (u+2/3u-1)+1=6-u/u+1 equation: 


D( u )

u = 0

u = 0

u = 0

u in (-oo:0) U (0:+oo)

u+(2/3)*u-1+1 = 1-(u/u)+6 // - 1-(u/u)+6

u+(2/3)*u+u/u-6-1-1+1 = 0

5/3*u-6 = 0 // + 6

5/3*u = 6 // : 5/3

u = 6/5/3

u = 18/5

u = 18/5

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