(u+3)/8=(u-9)/4+2

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Solution for (u+3)/8=(u-9)/4+2 equation: 



(u+3)/8=(u-9)/4+2

We move all terms to the left:

(u+3)/8-((u-9)/4+2)=0

We calculate fractions


(4u+12)/()+(-((u-9)*8)/()=0



We calculate terms in parentheses: +(-((u-9)*8)/(), so:

-((u-9)*8)/(

We multiply all the terms by the denominator


-((u-9)*8)



We calculate terms in parentheses: -((u-9)*8), so:

(u-9)*8

We multiply parentheses

8u-72

Back to the equation:

-(8u-72)



We get rid of parentheses

-8u+72

Back to the equation:

+(-8u+72)



We get rid of parentheses

(4u+12)/()-8u+72=0

We multiply all the terms by the denominator


(4u+12)-8u*()+72*()=0

We add all the numbers together, and all the variables

(4u+12)-8u*()=0

We get rid of parentheses

4u-8u*()+12=0

We move all terms containing u to the left, all other terms to the right

4u-8u*()=-12

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