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(u+3)=(u+1)
We move all terms to the left:
(u+3)-((u+1))=0
We get rid of parentheses
u-((u+1))+3=0
We calculate terms in parentheses: -((u+1)), so:We get rid of parentheses
(u+1)
We get rid of parentheses
u+1
Back to the equation:
-(u+1)
u-u-1+3=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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