(u+4)/3=(u-9)/8

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Solution for (u+4)/3=(u-9)/8 equation: 



(u+4)/3=(u-9)/8

We move all terms to the left:

(u+4)/3-((u-9)/8)=0

We calculate fractions


u/()+(-((u-9)*3)/()=0



We calculate terms in parentheses: +(-((u-9)*3)/(), so:

-((u-9)*3)/(

We multiply all the terms by the denominator


-((u-9)*3)



We calculate terms in parentheses: -((u-9)*3), so:

(u-9)*3

We multiply parentheses

3u-27

Back to the equation:

-(3u-27)



We get rid of parentheses

-3u+27

Back to the equation:

+(-3u+27)



We get rid of parentheses

u/()-3u+27=0

We multiply all the terms by the denominator


u-3u*()+27*()=0

We add all the numbers together, and all the variables

u-3u*()=0

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