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(u+6)(u+4)=18+5u
We move all terms to the left:
(u+6)(u+4)-(18+5u)=0
We add all the numbers together, and all the variables
(u+6)(u+4)-(5u+18)=0
We get rid of parentheses
(u+6)(u+4)-5u-18=0
We multiply parentheses ..
(+u^2+4u+6u+24)-5u-18=0
We get rid of parentheses
u^2+4u+6u-5u+24-18=0
We add all the numbers together, and all the variables
u^2+5u+6=0
a = 1; b = 5; c = +6;
Δ = b2-4ac
Δ = 52-4·1·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-1}{2*1}=\frac{-6}{2} =-3 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+1}{2*1}=\frac{-4}{2} =-2 $
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