(u+7)(u+2)=(u+5)(u+6)

Solution for (u+7)(u+2)=(u+5)(u+6) equation:

(u+7)(u+2)=(u+5)(u+6)

We move all terms to the left:

(u+7)(u+2)-((u+5)(u+6))=0

We multiply parentheses ..

(+u^2+2u+7u+14)-((u+5)(u+6))=0


We calculate terms in parentheses: -((u+5)(u+6)), so:

(u+5)(u+6)

We multiply parentheses ..

(+u^2+6u+5u+30)

We get rid of parentheses

u^2+6u+5u+30

We add all the numbers together, and all the variables

u^2+11u+30

Back to the equation:

-(u^2+11u+30)


We get rid of parentheses

u^2-u^2+2u+7u-11u+14-30=0

We add all the numbers together, and all the variables

-2u-16=0

We move all terms containing u to the left, all other terms to the right

-2u=16

u=16/-2

u=-8