(u-3)=3(u-4)-u+6

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Solution for (u-3)=3(u-4)-u+6 equation: 



(u-3)=3(u-4)-u+6

We move all terms to the left:

(u-3)-(3(u-4)-u+6)=0

We get rid of parentheses

u-(3(u-4)-u+6)-3=0



We calculate terms in parentheses: -(3(u-4)-u+6), so:

3(u-4)-u+6

We add all the numbers together, and all the variables

-1u+3(u-4)+6

We multiply parentheses

-1u+3u-12+6

We add all the numbers together, and all the variables

2u-6

Back to the equation:

-(2u-6)



We get rid of parentheses

u-2u+6-3=0

We add all the numbers together, and all the variables

-1u+3=0

We move all terms containing u to the left, all other terms to the right

-u=-3

u=-3/-1

u=+3

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