(u-5)(u-5)=0

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Solution for (u-5)(u-5)=0 equation: 



(u-5)(u-5)=0

We multiply parentheses ..

(+u^2-5u-5u+25)=0

We get rid of parentheses

u^2-5u-5u+25=0

We add all the numbers together, and all the variables

u^2-10u+25=0

a = 1; b = -10; c = +25;
Δ = b2-4ac
Δ = -102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$u=\frac{-b}{2a}=\frac{10}{2}=5$

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