(u-5)/8=7-(9u+6)/2

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Solution for (u-5)/8=7-(9u+6)/2 equation: 



(u-5)/8=7-(9u+6)/2

We move all terms to the left:

(u-5)/8-(7-(9u+6)/2)=0

We calculate fractions


u/()+(-(7-(9u+6)*8)/()=0



We calculate terms in parentheses: +(-(7-(9u+6)*8)/(), so:

-(7-(9u+6)*8)/(

We multiply all the terms by the denominator


-(7-(9u+6)*8)



We calculate terms in parentheses: -(7-(9u+6)*8), so:

7-(9u+6)*8

determiningTheFunctionDomain
-(9u+6)*8+7

We multiply parentheses

-72u-48+7

We add all the numbers together, and all the variables

-72u-41

Back to the equation:

-(-72u-41)



We get rid of parentheses

72u+41

Back to the equation:

+(72u+41)



We get rid of parentheses

u/()+72u+41=0

We multiply all the terms by the denominator


u+72u*()+41*()=0

We add all the numbers together, and all the variables

u+72u*()=0

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