(v)(v)=(2v-15)(v+4)

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Solution for (v)(v)=(2v-15)(v+4) equation: 



(v)(v)=(2v-15)(v+4)

We move all terms to the left:

(v)(v)-((2v-15)(v+4))=0

We multiply parentheses ..

-((+2v^2+8v-15v-60))+vv=0



We calculate terms in parentheses: -((+2v^2+8v-15v-60)), so:

(+2v^2+8v-15v-60)

We get rid of parentheses

2v^2+8v-15v-60

We add all the numbers together, and all the variables

2v^2-7v-60

Back to the equation:

-(2v^2-7v-60)



We get rid of parentheses

-2v^2+7v+vv+60=0

We move all terms containing v to the left, all other terms to the right

-2v^2+7v+vv=-60

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