(v+1)(v+2)=0

Solution for (v+1)(v+2)=0 equation:

Simplifying
(v + 1)(v + 2) = 0

Reorder the terms:
(1 + v)(v + 2) = 0

Reorder the terms:
(1 + v)(2 + v) = 0

Multiply (1 + v) * (2 + v)
(1(2 + v) + v(2 + v)) = 0
((2 * 1 + v * 1) + v(2 + v)) = 0
((2 + 1v) + v(2 + v)) = 0
(2 + 1v + (2 * v + v * v)) = 0
(2 + 1v + (2v + v2)) = 0

Combine like terms: 1v + 2v = 3v
(2 + 3v + v2) = 0

Solving
2 + 3v + v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(2 + v)(1 + v) = 0

Subproblem 1
Set the factor '(2 + v)' equal to zero and attempt to solve:

Simplifying
2 + v = 0

Solving
2 + v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + v = 0 + -2

Combine like terms: 2 + -2 = 0
0 + v = 0 + -2
v = 0 + -2

Combine like terms: 0 + -2 = -2
v = -2

Simplifying
v = -2
Subproblem 2
Set the factor '(1 + v)' equal to zero and attempt to solve:

Simplifying
1 + v = 0

Solving
1 + v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + v = 0 + -1

Combine like terms: 1 + -1 = 0
0 + v = 0 + -1
v = 0 + -1

Combine like terms: 0 + -1 = -1
v = -1

Simplifying
v = -1
Solution
v = {-2, -1}