(v+5)(-6v+1)=0

Solution for (v+5)(-6v+1)=0 equation:

(v+5)(-6v+1)=0

We multiply parentheses ..

(-6v^2+v-30v+5)=0

We get rid of parentheses

-6v^2+v-30v+5=0

We add all the numbers together, and all the variables

-6v^2-29v+5=0

a = -6; b = -29; c = +5;
Δ = b2-4ac
Δ = -292-4·(-6)·5
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-31}{2*-6}=\frac{-2}{-12}
=1/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+31}{2*-6}=\frac{60}{-12}
=-5
$