(v-4)(5v+7)=0

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Solution for (v-4)(5v+7)=0 equation:



(v-4)(5v+7)=0
We multiply parentheses ..
(+5v^2+7v-20v-28)=0
We get rid of parentheses
5v^2+7v-20v-28=0
We add all the numbers together, and all the variables
5v^2-13v-28=0
a = 5; b = -13; c = -28;
Δ = b2-4ac
Δ = -132-4·5·(-28)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-27}{2*5}=\frac{-14}{10} =-1+2/5 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+27}{2*5}=\frac{40}{10} =4 $

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