(v/3)+(3/4)=(-1/8)

Solution for (v/3)+(3/4)=(-1/8) equation:

(v/3)+(3/4)=(-1/8)

We move all terms to the left:

(v/3)+(3/4)-((-1/8))=0

We add all the numbers together, and all the variables

(+v/3)+(+3/4)-((-1/8))=0

We get rid of parentheses

v/3+3/4-((-1/8))=0

We calculate fractions


256v^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

256v^2/()+2=0

We multiply all the terms by the denominator


256v^2+2*()=0

We add all the numbers together, and all the variables

256v^2=0

a = 256; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·256·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{512}=0$