(v/5)=(3/11)

Solution for (v/5)=(3/11) equation:

(v/5)=(3/11)

We move all terms to the left:

(v/5)-((3/11))=0

We add all the numbers together, and all the variables

(+v/5)-((+3/11))=0

We get rid of parentheses

v/5-((+3/11))=0

We calculate fractions


11v^2/()+()/()=0

We add all the numbers together, and all the variables

11v^2/()+1=0

We multiply all the terms by the denominator


11v^2+1*()=0

We add all the numbers together, and all the variables

11v^2=0

a = 11; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·11·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{0}{22}=0$