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(w)(w+7)=360
We move all terms to the left:
(w)(w+7)-(360)=0
We multiply parentheses
w^2+7w-360=0
a = 1; b = 7; c = -360;
Δ = b2-4ac
Δ = 72-4·1·(-360)
Δ = 1489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1489}}{2*1}=\frac{-7-\sqrt{1489}}{2} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1489}}{2*1}=\frac{-7+\sqrt{1489}}{2} $
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