(w+1)+7=3(w-2)+2w

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Solution for (w+1)+7=3(w-2)+2w equation: 



(w+1)+7=3(w-2)+2w

We move all terms to the left:

(w+1)+7-(3(w-2)+2w)=0

We get rid of parentheses

w-(3(w-2)+2w)+1+7=0



We calculate terms in parentheses: -(3(w-2)+2w), so:

3(w-2)+2w

We add all the numbers together, and all the variables

2w+3(w-2)

We multiply parentheses

2w+3w-6

We add all the numbers together, and all the variables

5w-6

Back to the equation:

-(5w-6)



We add all the numbers together, and all the variables

w-(5w-6)+8=0

We get rid of parentheses

w-5w+6+8=0

We add all the numbers together, and all the variables

-4w+14=0

We move all terms containing w to the left, all other terms to the right

-4w=-14

w=-14/-4

w=3+1/2

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