(w+16)(w-9)=0

Solution for (w+16)(w-9)=0 equation:

(w+16)(w-9)=0

We multiply parentheses ..

(+w^2-9w+16w-144)=0

We get rid of parentheses

w^2-9w+16w-144=0

We add all the numbers together, and all the variables

w^2+7w-144=0

a = 1; b = 7; c = -144;
Δ = b2-4ac
Δ = 72-4·1·(-144)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-25}{2*1}=\frac{-32}{2}
=-16
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+25}{2*1}=\frac{18}{2}
=9
$