(w+2)(6w+11)=0

Solution for (w+2)(6w+11)=0 equation:

(w+2)(6w+11)=0

We multiply parentheses ..

(+6w^2+11w+12w+22)=0

We get rid of parentheses

6w^2+11w+12w+22=0

We add all the numbers together, and all the variables

6w^2+23w+22=0

a = 6; b = 23; c = +22;
Δ = b2-4ac
Δ = 232-4·6·22
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-1}{2*6}=\frac{-24}{12}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+1}{2*6}=\frac{-22}{12}
=-1+5/6
$