(w+2)(w-5)=w2-4

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Solution for (w+2)(w-5)=w2-4 equation:



(w+2)(w-5)=w2-4
We move all terms to the left:
(w+2)(w-5)-(w2-4)=0
We add all the numbers together, and all the variables
-(+w^2-4)+(w+2)(w-5)=0
We get rid of parentheses
-w^2+(w+2)(w-5)+4=0
We multiply parentheses ..
-w^2+(+w^2-5w+2w-10)+4=0
We add all the numbers together, and all the variables
-1w^2+(+w^2-5w+2w-10)+4=0
We get rid of parentheses
-1w^2+w^2-5w+2w-10+4=0
We add all the numbers together, and all the variables
-3w-6=0
We move all terms containing w to the left, all other terms to the right
-3w=6
w=6/-3
w=-2

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