(w+3)/4w+1=(w-5)/w

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Solution for (w+3)/4w+1=(w-5)/w equation: 



(w+3)/4w+1=(w-5)/w

We move all terms to the left:

(w+3)/4w+1-((w-5)/w)=0



Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R





Domain of the equation: w)!=0

w!=0/1

w!=0

w∈R



We calculate fractions


(w+3)*w)/4w^2+(-((w-5)*4w)/4w^2+1=0

We calculate fractions


((w+3)*w)*4w^2)/(4w^2+(*4w^2)+(-((w-5)*4w)*4w^2)/(4w^2+(*4w^2)+1=0

We get rid of parentheses

((w+3)*w)*4w^2)/(4w^2+*4w^2+(-((w-5)*4w)*4w^2)/(4w^2+(*4w^2)+1=0

We calculate fractions


*4w^2+(((w+3)*w)*4w^2)*(4w^2+*4w^2+1)/((4w^2*(4w^2+(*4w^2)+1)+((-((w-5)*4w)*4w^2)*4w^2/((4w^2*(4w^2+(*4w^2)+1)=0



We calculate terms in parentheses: +(((w+3)*w)*4w^2)*(4w^2+*4w^2+1)/((4w^2*(4w^2+(*4w^2)+1)+((-((w-5)*4w)*4w^2)*4w^2/((4w^2*(4w^2+(*4w^2)+1), so:

((w+3)*w)*4w^2)*(4w^2+*4w^2+1)/((4w^2*(4w^2+(*4w^2)+1)+((-((w-5)*4w)*4w^2)*4w^2/((4w^2*(4w^2+(*4w^2)+1

We can not solve this equation

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