(w+7)(w-15)=0

Solution for (w+7)(w-15)=0 equation:

(w+7)(w-15)=0

We multiply parentheses ..

(+w^2-15w+7w-105)=0

We get rid of parentheses

w^2-15w+7w-105=0

We add all the numbers together, and all the variables

w^2-8w-105=0

a = 1; b = -8; c = -105;
Δ = b2-4ac
Δ = -82-4·1·(-105)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-22}{2*1}=\frac{-14}{2}
=-7
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+22}{2*1}=\frac{30}{2}
=15
$