(w+7)/(w-3)+1=(w+2)/(w-2)

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Solution for (w+7)/(w-3)+1=(w+2)/(w-2) equation:


D( w )

w-3 = 0

w-2 = 0

w-3 = 0

w-3 = 0

w-3 = 0 // + 3

w = 3

w-2 = 0

w-2 = 0

w-2 = 0 // + 2

w = 2

w in (-oo:2) U (2:3) U (3:+oo)

(w+7)/(w-3)+1 = (w+2)/(w-2) // - (w+2)/(w-2)

(w+7)/(w-3)-((w+2)/(w-2))+1 = 0

(w+7)/(w-3)+(-1*(w+2))/(w-2)+1 = 0

((w+7)*(w-2))/((w-3)*(w-2))+(-1*(w+2)*(w-3))/((w-3)*(w-2))+(1*(w-3)*(w-2))/((w-3)*(w-2)) = 0

(w+7)*(w-2)-1*(w+2)*(w-3)+1*(w-3)*(w-2) = 0

w^2+6*w-5*w-8+6 = 0

w^2+w-2 = 0

w^2+w-2 = 0

w^2+w-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

w = (9^(1/2)-1)/(1*2) or w = (-9^(1/2)-1)/(1*2)

w = 1 or w = -2

(w+2)*(w-1) = 0

((w+2)*(w-1))/((w-3)*(w-2)) = 0

((w+2)*(w-1))/((w-3)*(w-2)) = 0 // * (w-3)*(w-2)

(w+2)*(w-1) = 0

( w+2 )

w+2 = 0 // - 2

w = -2

( w-1 )

w-1 = 0 // + 1

w = 1

w in { -2, 1 }

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