(w+9)(3w+1)=0

Solution for (w+9)(3w+1)=0 equation:

(w+9)(3w+1)=0

We multiply parentheses ..

(+3w^2+w+27w+9)=0

We get rid of parentheses

3w^2+w+27w+9=0

We add all the numbers together, and all the variables

3w^2+28w+9=0

a = 3; b = 28; c = +9;
Δ = b2-4ac
Δ = 282-4·3·9
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-26}{2*3}=\frac{-54}{6}
=-9
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+26}{2*3}=\frac{-2}{6}
=-1/3
$