(w-2/w+6)+1=w+2/w+3

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Solution for (w-2/w+6)+1=w+2/w+3 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w-(2/w)+1+6 = w+2/w+3 // - w+2/w+3

w-w-(2/w)-(2/w)-3+1+6 = 0

w-w-2*w^-1-2*w^-1-3+1+6 = 0

-4*w^-1 = -4 // : -4

w^-1 = 1

-1 < 0

1/(w^1) = 1 // * w^1

1 = 1*w^1 // : 1

1 = w^1

w = 1

w = 1

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