(w-5)*(w-5)=0

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Solution for (w-5)*(w-5)=0 equation: 



(w-5)(w-5)=0

We multiply parentheses ..

(+w^2-5w-5w+25)=0

We get rid of parentheses

w^2-5w-5w+25=0

We add all the numbers together, and all the variables

w^2-10w+25=0

a = 1; b = -10; c = +25;
Δ = b2-4ac
Δ = -102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{10}{2}=5$

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