(w/(2w-3))=4/w

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Solution for (w/(2w-3))=4/w equation:


D( w )

2*w-3 = 0

w = 0

2*w-3 = 0

2*w-3 = 0

2*w-3 = 0 // + 3

2*w = 3 // : 2

w = 3/2

w = 0

w = 0

w in (-oo:0) U (0:3/2) U (3/2:+oo)

w/(2*w-3) = 4/w // - 4/w

w/(2*w-3)-(4/w) = 0

w/(2*w-3)-4*w^-1 = 0

w/(2*w-3)-4/w = 0

(w^2)/(w*(2*w-3))+(-4*(2*w-3))/(w*(2*w-3)) = 0

w^2-4*(2*w-3) = 0

w^2-8*w+12 = 0

w^2-8*w+12 = 0

w^2-8*w+12 = 0

DELTA = (-8)^2-(1*4*12)

DELTA = 16

DELTA > 0

w = (16^(1/2)+8)/(1*2) or w = (8-16^(1/2))/(1*2)

w = 6 or w = 2

(w-2)*(w-6) = 0

((w-2)*(w-6))/(w*(2*w-3)) = 0

((w-2)*(w-6))/(w*(2*w-3)) = 0 // * w*(2*w-3)

(w-2)*(w-6) = 0

( w-2 )

w-2 = 0 // + 2

w = 2

( w-6 )

w-6 = 0 // + 6

w = 6

w in { 2, 6 }

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